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-2x^2+260x-5000=0
a = -2; b = 260; c = -5000;
Δ = b2-4ac
Δ = 2602-4·(-2)·(-5000)
Δ = 27600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{27600}=\sqrt{400*69}=\sqrt{400}*\sqrt{69}=20\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(260)-20\sqrt{69}}{2*-2}=\frac{-260-20\sqrt{69}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(260)+20\sqrt{69}}{2*-2}=\frac{-260+20\sqrt{69}}{-4} $
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